2x^2-1x=-1x^2

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Solution for 2x^2-1x=-1x^2 equation:



2x^2-1x=-1x^2
We move all terms to the left:
2x^2-1x-(-1x^2)=0
We get rid of parentheses
2x^2+1x^2-1x=0
We add all the numbers together, and all the variables
3x^2-1x=0
a = 3; b = -1; c = 0;
Δ = b2-4ac
Δ = -12-4·3·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-1}{2*3}=\frac{0}{6} =0 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+1}{2*3}=\frac{2}{6} =1/3 $

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